4(x^2+5)=2(x^2+1)

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Solution for 4(x^2+5)=2(x^2+1) equation:


Simplifying
4(x2 + 5) = 2(x2 + 1)

Reorder the terms:
4(5 + x2) = 2(x2 + 1)
(5 * 4 + x2 * 4) = 2(x2 + 1)
(20 + 4x2) = 2(x2 + 1)

Reorder the terms:
20 + 4x2 = 2(1 + x2)
20 + 4x2 = (1 * 2 + x2 * 2)
20 + 4x2 = (2 + 2x2)

Solving
20 + 4x2 = 2 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
20 + 4x2 + -2x2 = 2 + 2x2 + -2x2

Combine like terms: 4x2 + -2x2 = 2x2
20 + 2x2 = 2 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
20 + 2x2 = 2 + 0
20 + 2x2 = 2

Add '-20' to each side of the equation.
20 + -20 + 2x2 = 2 + -20

Combine like terms: 20 + -20 = 0
0 + 2x2 = 2 + -20
2x2 = 2 + -20

Combine like terms: 2 + -20 = -18
2x2 = -18

Divide each side by '2'.
x2 = -9

Simplifying
x2 = -9

Reorder the terms:
9 + x2 = -9 + 9

Combine like terms: -9 + 9 = 0
9 + x2 = 0

The solution to this equation could not be determined.

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